x^2-12x+40=1

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Solution for x^2-12x+40=1 equation:


Simplifying
x2 + -12x + 40 = 1

Reorder the terms:
40 + -12x + x2 = 1

Solving
40 + -12x + x2 = 1

Solving for variable 'x'.

Reorder the terms:
40 + -1 + -12x + x2 = 1 + -1

Combine like terms: 40 + -1 = 39
39 + -12x + x2 = 1 + -1

Combine like terms: 1 + -1 = 0
39 + -12x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-39' to each side of the equation.
39 + -12x + -39 + x2 = 0 + -39

Reorder the terms:
39 + -39 + -12x + x2 = 0 + -39

Combine like terms: 39 + -39 = 0
0 + -12x + x2 = 0 + -39
-12x + x2 = 0 + -39

Combine like terms: 0 + -39 = -39
-12x + x2 = -39

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -39 + 36

Reorder the terms:
36 + -12x + x2 = -39 + 36

Combine like terms: -39 + 36 = -3
36 + -12x + x2 = -3

Factor a perfect square on the left side:
(x + -6)(x + -6) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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